Modern4DaBois
Member
- Joined
- Oct 25, 2021
- Messages
- 42
- Gender
- Male
- HSC
- 2022
I get the first two parts. Those are ez. But how would you go about proving the third one? @jimmysmith560 help lol
-
Finished your HSC? Check out our University Discussion, Non-School forums or help out next year's HSC students! -
YOU can help the next generation of students in the community! Share your trial papers and notes on our Notes & Resources page
Help Pls with this Q (1 Viewer)
- Thread starter Modern4DaBois
- Start date
I get the first two parts. Those are ez. But how would you go about proving the third one? @jimmysmith560 help lol
LHS = (-1)^n
= (1+w)^3n
= RHS
Cancel out the 3nCm, mEZ, 3|m terms.
1/2((Rhs - those terms)x2)
= 1/2 ((3nC1 w+3nC3n-1 w^2) (was w^3n-1) + (3nC2 w+3nC3n-2 w^2) +...... ), for terms higher than w^3, divide by w^3k, kEZ to get either w or w^2
Using part i), and the nCm = nCn-m identity
= 1/2 (-3nC1 - 3nC2 - 3nC4 - 3nC5 .....)
= LHS - those terms
Last edited:
Would the following working help?
