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Help!Plz!!very urgent!! (1 Viewer)

linxicm

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Can anyone help me with this question? first derivative for :

f(X)=1/(X*LnX^2)

and


f(x) = 98+5x/(3x^2+1)

many tks!!!
 

lolokay

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using quotient rule: d/dx u/v = (v.du - u.dv)/v2
ln[x2] = 2lnx
d/dx 1/(2x ln[x])
= -(2ln[x] + 2)/(2x ln[x])2
= -(ln[x] + 1)/4x2lnx

d/dx (98+5x)/(3x2 + 1)
= ( 5(3x2 + 1) - 6x(98+5x) )/((3x2 + 1)2
= ( -15x2 - 588x + 5 )/(3x2 + 1)2


there's a derivative solver here: http://calc101.com/webMathematica/derivatives.jsp#topdoit
 
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lolokay

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wow, good question =/
"4U MATH: 94"
 

vds700

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linxicm said:
Can anyone help me with this question? first derivative for :

f(X)=1/(X*LnX^2)

and


f(x) = 98+5x/(3x^2+1)

many tks!!!
why u asking this if u did ure hsc 3 years ago?
 

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