Help with question please (1 Viewer)

Squar3root

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lhs = sin(x+30) + cos(x+30)

now cos(x) = sin (90-x)

so we get

sin(x+30) + sin(90 - (x+30))

= sin(x+30) + sin (60-x)

using sum to product we get

2sin( [x+30 +60+x ]/2) * cos ([x + 30 - (60 -x)]/2

= 2 sin(90/2) cos([2x-30]/2)

= sqrt(2)cos(x-15)
 

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