MedVision ad

Help with statistics problem (1 Viewer)

Invisible$_$

New Member
Joined
Jun 11, 2020
Messages
1
Gender
Female
HSC
2020
12CB892D-831F-4D87-AFBD-EAB25738121A.jpeg
Hello, can someone please help me with questions (c)(i) and (ii)?
 

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,384
Gender
Male
HSC
2006
Let D be the detected speed in the camera, S be the actual speed and E be the error such that E = D - S.

We are looking for the event that an infringement occurs (i.e. D > 80) and the actual speed is does not exceed 80 km/h (S < 80) for the two different values of the errors.

If the detected speed D is 2 km/h above the actual speed, then this event occurs when the actual speed S is between 78 km/h and 80 km/h.
If the detected speed D is 3 km/h above the actual speed, then this event occurs when the actual speed S is between 77 km/h and 80 km/h.
If the detected speed D is 1 km/h below the actual speed, then no infringement occurs

Hence, for part (i), we are looking for the following probability




Noting that the actual speed of the vehicle is independent of the type of error in the speed camera. For the second part, we are only looking at the first term of E = 2, as the event of E = -1 does not lead to an infringement (given S < 80) .

For part (ii), we are looking for the event of not having an infringement (i.e. D < 80) and the actual speed exceeds 80 km/h (S > 80)

If the detected speed D is 2 km/h above the actual speed, then an infringement will always occur for S > 80.
If the detected speed D is |2+α| km/h below the actual speed, then no infringement occurs provided 80 < S < 80-(2+α)

Note that a necessary condition for this to occur is α < -2 as the detected speed must always be below the actual speed to have no infringement if the actual speed already exceeds the limit of 80 km/h.

Hence, we are looking for the following probability




Let this equal to 7.125% and solve to get the boundary value for α (which should be negative). The range of values of α will then be between -2 and this value.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top