Help with Trig. question please (1 Viewer)

[chriskoss]

Hey ye'all..

Can't figure out this question.. so I'll try my best to write it up on 'teh computar'


Find the value of x in each of these triangles

 

[-tal-]

Hey ye'all..

Can't figure out this question.. so I'll try my best to write it up on 'teh computar'


Find the value of x in each of these triangles

Only saw 1 triangle but anyway:

sin x = 6/12
x = 30

 

[joker252]

Hey ye'all..

Can't figure out this question.. so I'll try my best to write it up on 'teh computar'


Find the value of x in each of these triangles

how can you not do this?

there is nothing complicated about it at all.

edit: ok i see. Bored of Studies > Secondary Education > New South Wales (HSC) > Maths > General Mathematics

 

[chriskoss]

how can you not do this?

there is nothing complicated about it at all.

edit: ok i see. Bored of Studies > Secondary Education > New South Wales (HSC) > Maths > General Mathematics

g-g-g-geez wait.. hold on their inspector gadget!

I asked cuz i dno how to do it.. shit .. FANCY DAT? Asking a question to get the answer

Im not good at trig or any maths for that matter

 

[chriskoss]

Only saw 1 triangle but anyway:

sin x = 6/12
x = 30

So wait do you go Sin multiplied by 6/12 ?

 

[laa.musique]

So wait do you go Sin multiplied by 6/12 ?

no. you do SHIFT SIN(6/12) on your calculator

 

[chriskoss]

Thankyou... it wasn't stated to do sin-1 only sin thats why i was like wtf.

Why is it sin-1... is it just used to find unknown angles?

Where as normal sin is used when there is 1 length (12 m) and 1 angle (30')

 

[Sargeyness]

Correct, sin-1 is used to find the unknown angle.