help!?! (1 Viewer)

[Maddy1012]

i have no idea what to do for this question...

a mass of 72.5g of ethanol was brnt completely in ar. Calculate the volume of C02 that wasproduced at 25 degrees celcius at 100kPa.

 

[Forbidden.]

i have no idea what to do for this question...

a mass of 72.5g of ethanol was brnt completely in ar. Calculate the volume of C02 that wasproduced at 25 degrees celcius at 100kPa.

Write your EQUATION (always always always do this when you can), oh and assume it completely burns up (enough or excess oxygen)

C₂H₅OH (l) + 3O₂ (g) ---> 3H₂O + 2CO₂


Convert the mass of ETHANOL to MOLES

72.5g/46g = 1.58 (to 2 decimal places)

(Because 46g of Ethanol is 1 MOLE.)



1M of ANY gas occupies 24.71 L @ 25 degrees AND 100kPa
(This 24.71L may vary with different textbooks.)

BUT

1 MOLE C₂H₅OH makes 2 MOLES of CO₂, but you have 1.58 MOLES

So we MULTIPLY the 1.58 by 2 = 5.16M


5.16 x 24.71 = 127.5L (to 1 decimal place)



OUR STATEMENT:

5.16M of CO₂ gas occupies 127.5L @ 25 degrees AND 100kPa

 

[Maddy1012]

1.58 times 2 isnt 5.16... but i get the drift... thankyou so so very much:wave: