mazza_728
Manda xoxo
One extremity of a focal chord in the parbol x^2=8y is t=3.
Find:
i) the gradient of the chord
As x^2 = 4ay
a=2
Also x=2at and y=at^2
Therefore x=12 and y=18
and focus = (0,2)
m=16/12
m=4/3
ii) the equation of the chord
y-y=m(x-x)
y-2=4/3(x-0)
3y-6=4x
4x-3y+6=0
iii) find cartesian co-ordinates of the other extremities of the chord.
I attempted to find point of intersection of x62=8y and 4x-3y+6=0 which i hoped would give me two points, one (12,18) which i already found and the other which would be the other extremity of the chord!
But on solving i found
x^2=8y
4x-3y+6=0
4x-24/x^2 + 6
4x^3+6x^2-24=0
2x^3+3x^2-12=0
Now my mind has either gone blank or i wouldnt have a clue how to solve the above equation.. can someone please help!! ASAP
Find:
i) the gradient of the chord
As x^2 = 4ay
a=2
Also x=2at and y=at^2
Therefore x=12 and y=18
and focus = (0,2)
m=16/12
m=4/3
ii) the equation of the chord
y-y=m(x-x)
y-2=4/3(x-0)
3y-6=4x
4x-3y+6=0
iii) find cartesian co-ordinates of the other extremities of the chord.
I attempted to find point of intersection of x62=8y and 4x-3y+6=0 which i hoped would give me two points, one (12,18) which i already found and the other which would be the other extremity of the chord!
But on solving i found
x^2=8y
4x-3y+6=0
4x-24/x^2 + 6
4x^3+6x^2-24=0
2x^3+3x^2-12=0
Now my mind has either gone blank or i wouldnt have a clue how to solve the above equation.. can someone please help!! ASAP