Helping me helps yourself so do it...do it..haha (1 Viewer)

[FcUk]

This question i know wat to do until i derive tanx... anyway here goes

Find the equation of the tangent to the curve y=tanx at the point where x=3pi/4

i just dont kno how to solve y'=sec^2(3pi/4) to find the gradient

Thanking you in advance

 

[Xayma]

dy/dx=sec² 3π/4
=1/cos² 3π/4
=1/(-1/√ 2)²
=2

 

[jumb]

Put it into your calculator, it equals 2