how do you draw cosec graphs (1 Viewer)

[jessi90]

e.g. y = cosec4x

 

[dolbinau]

I just sub values to find asymptotes, the shape in general etc..

If someone has a better method I'd also be interested .

 

[FatJ]

it's kind of the opposite to a sin graph
basically get the sin graph with pi/2 as the period, amplitude as 1
so from 0 to pi/4, the curve goes from 1 to 0 to 1, and then from pi/4 to pi/2, the curve starts from -1, goes to 0, and then goes to -1 again.
I'm crap at describing but hopefully you get the idea.

 

[Timothy.Siu]

asymptotes is obviously where the denominator = 0.
are uu sure we need to know this for 2unit?

 

[shaon0]

e.g. y = cosec4x

since, cosec4x=1/sin4x.
When sin4x=0 the function is undefined so those are your asymptotes.
And it follows the sin graph reverse continuity shape.