how do you sketch f"(x) from f'(x) (1 Viewer)

[highshill]

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[InteGrand]

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[highshill]

So do we follow the same principle :
f'(x) to f(x)
Find Stationary Point
if line/curve is above the x-axis the gradient is positive and if the graph is below the gradient is negative
Sketch according to slope

So for f'(x) to f"(x)
Same thing

 

[captainhelium]

So do we follow the same principle :
f'(x) to f(x)
Find Stationary Point
if line/curve is above the x-axis the gradient is positive and if the graph is below the gradient is negative
Sketch according to slope

So for f'(x) to f"(x)
Same thing

Yeah its the same process as sketching f(x) to f'(x).

- Stationary points become x-intercepts
- Parts with a positive gradient are above the x axis
- Parts with a negative gradient are below the x axis