I can't get the answer. (1 Viewer)

[taggs-sasuke]

Find the integral, between 0 and In2, of:
e^x / ( e^x + 1 ) .dx


(Does that make sense?)


The answer is:
In(3/2)


Thanks in advance!

 

[Templar]

Find the integral, between 0 and In2, of:
e^x / ( e^x + 1 ) .dx


(Does that make sense?)


The answer is:
In(3/2)


Thanks in advance!

Substitute , new limits are 1 and 2, we get

 

[Timothy.Siu]

Find the integral, between 0 and In2, of:
e^x / ( e^x + 1 ) .dx


(Does that make sense?)


The answer is:
In(3/2)


Thanks in advance!

S f'(x)/f(x)=ln f(x)

so..
the integral, between 0 and In2, of:
e^x / ( e^x + 1 ) .dx
=[ln(e^x+1)]ln2,0
=ln(2+1)-ln(1+1)=ln(3/2)

 

[taggs-sasuke]

Templar:

I haven't learnt substitution yet so I don't know how you got the new limits. Thank you for answering though.

Timothy.Siu:

Man, that was very straightforward. Thank you for pointing it out for me - *feels stupid*.