integration help (1 Viewer)
- Thread starter lolzlolz
- Start date
daddythicclegs
Member
- Joined
- Dec 9, 2020
- Messages
- 7
- Gender
- Male
- HSC
- N/A
Integrate f'(x) to get (f(x) = 2x^3/3+3x^2/2-6x+C) and then because f(1)=3, you let 3 = the integral with 1 subbed in for the x's and find C.
5uckerberg
Well-Known Member
- Joined
- Oct 15, 2021
- Messages
- 562
- Gender
- Male
- HSC
- 2018
With these questions the first task would be to find the primitive and noticably we first have the derivative.
Note primitive is the opposite of derivative so the opposite of differentiating is integrating.
Now, we start with=2x^{2}+3x-6)
we already have the derivative and we also know that =3)
,
So integrating we will have=\frac{2x^{3}}{3}+\frac{3x^{2}}{2}-6x+C)
.
Remember we are told that so sub 
into )
=\frac{2}{3}+\frac{3}{2}-6+C=3)
Note primitive is the opposite of derivative so the opposite of differentiating is integrating.
Now, we start with
So integrating we will have
Remember we are told that
5uckerberg
Well-Known Member
- Joined
- Oct 15, 2021
- Messages
- 562
- Gender
- Male
- HSC
- 2018
From your posts @lolzlolz I think a word of advice is to continue practising these concepts until they become second nature. The reason you struggle is that you forget the building blocks that are used to construct the formulas. No worries develop an understanding of why these formulas work and know why it is the case through visual means and you will be solid as a rock in mathematics.