Thanks, i didn't think of that.pLuvia said:Just split the fraction into 2 i.e. 1/x2-x/x2 then integrate
I got 27/4. But I'm not sure.shaon0 said:Find the area bounded by y=((x^2)/4) -2 and y=x+1.
I have got the answer but i don't know whether it is correct.
100/3 is my answer. Could someone please verify this?
....I forgot to integrate my 1/x^2. loltommykins said:y² = 1/x²
v = pi int x^-2 dx 4->1
= pi [ -x^-1 ] 4->1
= pi [ -1/4 - [-1/1] ]
= pi [ -1/4 + 1 ]
= 3pi/4
No...around the y-axis. so you sub the x-values into one of the equations.lolokay said:x3 - 16x = 0
x = 0, 4
pi Int (x6/64) - 4x2
= pi [x7/(64*7) - 4/3 x3]4,0
=~ 153.19
is that what you got?
Yea i figured it out before i saw your solution. I forgot to put a 2^2 in front of one of 32 when integrating for some reason.lolokay said:oh didn't see that bit
by rearranging the equations you get
x2 = y2/4 and x2 = 4y2/3
with intercepts y=0,8
pi Int y2/4 - 4y2/3
= pi(y3/12 - 12/5 y5/3) for y=8
= 128pi/3 - 384pi/5
= -107.233
so volume = 107.233
your answer was close. got 32 instead of 128