Integration Questiom (1 Viewer)

nrumble42 · Jan 30, 2017

Calculate the area of the region bounded by the curve y=2x^2(4-x) and the x-axis.

Thanks

InteGrand · Jan 30, 2017

nrumble42 said:
Calculate the area of the region bounded by the curve y=2x^2(4-x) and the x-axis.

Thanks

$\noindent If we sketch the curve, if is clear we want the area under the curve between $x=0$ and $4$. So the area will be given by $A = \int_{0}^{4}2x^{2}(4-x)\,\mathrm{d}x$. Expanding, we have $A = \int_{0}^{4}\left(8x^{2} -2x^{3}\right)\, \mathrm{d}x$. You should be able to evaluate the integral from here to get the answer.$

nrumble42 · Jan 30, 2017

Ooh right of course haha. When I did it, I found the x-intercepts and i forgot to draw one of them (cant remember atm) as the double root. But thankyou heaps!

Integration Questiom (1 Viewer)

nrumble42

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InteGrand

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nrumble42

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