Integration question (1 Viewer)

[Gavvvvvin]

How do you integrate

3sinx​

cosx + 1​

 

[redruM]

using #f'(x)/f(x) = log f(x)

try that, it is going to be on your table of standard integrals.

edit: # = integral sign

 

[Gavvvvvin]

But it isnt in the form f'(x)/f(x) is it?

 

[redruM]

d/dx(cosx + 1) = - sinx + 0 = - sinx

 

[pc_wizz]

∫3sinx/(cosx + 1)
= -3∫(-sinx)/(cosx + 1)
= -3.ln (cosx + 1) + c