L Li0n spiKu Joined Dec 28, 2002 Messages 953 Location not telling Gender Female HSC 2004 Sep 8, 2004 #1 Topic ^^ was in JR ext-1 trial 04 paper if your wondering
A ae Member Joined Apr 9, 2003 Messages 161 Gender Male HSC 2004 Sep 8, 2004 #2 swap x&y so, x=e^2y+e^y then, (e^y)^2 +e^y - x = 0 then use quadractic formula. e^y= ...... then y= ln.....
swap x&y so, x=e^2y+e^y then, (e^y)^2 +e^y - x = 0 then use quadractic formula. e^y= ...... then y= ln.....
Archman Member Joined Jul 29, 2003 Messages 337 Gender Undisclosed HSC N/A Sep 8, 2004 #3 ye, just keep in mind that e^y is positive.
L Li0n spiKu Joined Dec 28, 2002 Messages 953 Location not telling Gender Female HSC 2004 Sep 8, 2004 #4 thanks homie ^_^
I Iota Guest Sep 9, 2004 #5 f(x)=e^x+e^2x ln(f(x))=x+2x=3x, divide by 3 and interchange f(x) and x (1/3)lnx=f^-1(x) So why did I get it wrong?
f(x)=e^x+e^2x ln(f(x))=x+2x=3x, divide by 3 and interchange f(x) and x (1/3)lnx=f^-1(x) So why did I get it wrong?
E Estel Tutor Joined Nov 12, 2003 Messages 1,261 Gender Male HSC 2005 Sep 9, 2004 #6 When you take the ln of the LHS you have to do it to the whole of the LHS, not just individual terms. i.e. x + y = z then (x+y)^2 = z^2 not x^2 + y^2 = z^2
When you take the ln of the LHS you have to do it to the whole of the LHS, not just individual terms. i.e. x + y = z then (x+y)^2 = z^2 not x^2 + y^2 = z^2
ngai Member Joined Mar 24, 2004 Messages 223 Gender Male HSC 2004 Sep 9, 2004 #8 ahh, that question...haha