irrational distance (1 Viewer)

Mahan1 · Mar 5, 2017

$\textrm{Find the minimum number of points on a complex plane such that}$ $\textrm{for any arbitrary point on the plane at least one the distance between that arbitrary point}$
$\textrm{to the chosen points is irrational.}$

$\textrm{For instance, suppose the minimum number of points}$
$\textrm{ satisfying the condition is 2}.$
$\textrm{Let us call those points} P_{1} \ \textrm{and} \ P_{2}$

$\textrm{but if M lies on the perpendicular bisector of the segment }P_{1},P_{2}$

$\textrm{such that} \ MP_{1} \ \textrm{is rational.Since MAB is isosceles then } \ MP_{2} \ \textrm{is also rational}$

$\textrm{Since we found the point on the plane such that the distance between}$

$P_{1}, P_{2}$
$\textrm{is rational then the minimum number of points satisfying the condition should be at least 3.}$

Paradoxica · Mar 6, 2017

Sense this question does not make.

-insert yoda picture here-

Context it lacks.

irrational distance (1 Viewer)

Mahan1

Member

Paradoxica

-insert title here-

Users Who Are Viewing This Thread (Users: 0, Guests: 1)