weirdguy99
Member
This experiment is from the Jacaranda HSC Science Physics 2 book. (pg 11 analysis questions if you have the book)
As I understand,
>From the Period formula (T=2*pi root l/g <-cbf to write properly), you can make it [4*(pi)^2]/g = T^2/L.
>T^2/L is m(gradient) as T^2 is the y axis and L is the x axis (grad=rise over run). Therefore 4*(pi)^2/g is also m.
A previous question also told you to find out that T^2 = K * L. Therefore K = T^2/L which furthermore proves the point above.
Therefore the gradient is [4*(pi)^2]/g, but since your finding the value of gravity you must use T^2/L to find the gradient. The answer should be somewhere near 9.8ms^2 depending on some minor variables in the actual pendulum experiment.
Is this all correct?
What a hefty post to type up...... Btw I know that there is a post about this experiment but it was all cluttered and I couldnt be bothered to ask there.
As I understand,
>From the Period formula (T=2*pi root l/g <-cbf to write properly), you can make it [4*(pi)^2]/g = T^2/L.
>T^2/L is m(gradient) as T^2 is the y axis and L is the x axis (grad=rise over run). Therefore 4*(pi)^2/g is also m.
A previous question also told you to find out that T^2 = K * L. Therefore K = T^2/L which furthermore proves the point above.
Therefore the gradient is [4*(pi)^2]/g, but since your finding the value of gravity you must use T^2/L to find the gradient. The answer should be somewhere near 9.8ms^2 depending on some minor variables in the actual pendulum experiment.
Is this all correct?
What a hefty post to type up...... Btw I know that there is a post about this experiment but it was all cluttered and I couldnt be bothered to ask there.
