N Newbit Member Joined May 1, 2012 Messages 64 Gender Male HSC 2012 Sep 9, 2012 #1 Hey Guys, I'm having some trouble solving this question. For the Geometric Series r= -tan^2(Theta) For what values of theta in the interval -Pi/2 < Theta < Pi/2 does the limiting sum of the series exist?
Hey Guys, I'm having some trouble solving this question. For the Geometric Series r= -tan^2(Theta) For what values of theta in the interval -Pi/2 < Theta < Pi/2 does the limiting sum of the series exist?
Carrotsticks Retired Joined Jun 29, 2009 Messages 9,494 Gender Undisclosed HSC N/A Sep 9, 2012 #2 A limiting sum exists if -1 < R < 1. -1 < - tan^2 (x) < 1 But - tan^2 (x) < 1 for all real x, so the inequality is essentially: -1 < - tan^2 (x) <= 0 Or to re-write it: 0 <= tan^2 (x) < 1 -1 < tan(x) < 1 - pi/4 < tan(x) < pi/4.
A limiting sum exists if -1 < R < 1. -1 < - tan^2 (x) < 1 But - tan^2 (x) < 1 for all real x, so the inequality is essentially: -1 < - tan^2 (x) <= 0 Or to re-write it: 0 <= tan^2 (x) < 1 -1 < tan(x) < 1 - pi/4 < tan(x) < pi/4.