Maths Help Please :) (1 Viewer)

Redyapper · Feb 5, 2013

Hi,

I'm sure this is a very easy question, I just don't know what to do since the highest power after I find the first derivative is 3 (so how do I find what x is basically...?)

The question is:
For y=3x^4 + 8x^3 - 48x^2 +1, find any stationary points and determine their nature.

So I find the first derivative, and I get 12x^3 + 24x^2 - 96, and then equate it to 0 to find the x values of the stationary points... but I don't know how to find x.

Thanks for any help!

asianese · Feb 5, 2013

$y=3x^4+8x^3-48x^2+1\\ \frac{dy}{dx}= 12x^3+24x^3-96x \\ \text{For stationary points, } \frac{dy}{dx}=0\\ \therefore 12x^3+24x^3-96x=0\\ x^3+2x^2-8x=0$

You can solve the equation from there.

Maths Help Please :) (1 Viewer)

Redyapper

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asianese

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