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kelly_xxx

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A point A lies on the curve y= x(5-x), and a point B with the same x coordinate as A lies on the curve y=x(x-3). Show this information on a diagram , then find an expression for the length of AB, and determine the max. length if 0<x<4 (this is meant to be smaller equal than)

Would u be able to show me the working? Much appreciated.
 
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Riviet

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Let co-ordinates of A be (x,y1) and B be (x,y2)
Use distance formula:
d=sqrt[(y2-y1)2-(x-x)]
=sqrt(y2-y1)2
=|y2-y1|

Please clarify what you mean by 0<4. :)
 
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Sober

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kelly_xxx said:
A point A lies on the curve y= x(5-x), and a point B with the same x coordinate as A lies on the curve y=x(x-3). Show this information on a diagram , then find an expression for the length of AB, and determine the max. length if 0<x<4 (this is meant to be smaller equal than)

Would u be able to show me the working? Much appreciated.
The distance will be the absolute difference of the two y values as Riviet stated:

AB = | x(5-x) - x(x-3) |

= | 2x2 - 8x |

And I assume you were looking for the maximum for 0 ≤x ≤ 4, so for a porabola this is going to be either the turning point (if it is in the range), or the defined end points at 0 and 4:

Turning point = 2, 8
End points = (0,0), (4,0);

The turning point is in the range and is greater than the end points so the answer is 8.
 

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