Mod 6 Q (1 Viewer)

hmim · Apr 10, 2023

How would you go about doing f) (it's actually part c) but its an error in the solutions). ?

jimmysmith560 · Apr 10, 2023

Would the following help?

When the voltage is halved to 250 kV, the transmission line current will be doubled.
∴ Power loss is 4 times that at 500 kV.

That is:

$I\times 2\:\text{(to 400A)}$

$P_{\text{loss}}=I^2R$

$P_{\text{loss}}=400^2\times 3$

$P_{\text{loss}}=4.8\times 10^5\:W$

⟹ Factor of 4.

hmim · Apr 11, 2023

jimmysmith560 said:
Would the following help?

When the voltage is halved to 250 kV, the transmission line current will be doubled.
∴ Power loss is 4 times that at 500 kV.

That is:

$I\times 2\:\text{(to 400A)}$

$P_{\text{loss}}=I^2R$

$P_{\text{loss}}=400^2\times 3$

$P_{\text{loss}}=4.8\times 10^5\:W$

⟹ Factor of 4.

Oh yes, thanks!

Mod 6 Q (1 Viewer)

hmim

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hmim

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