Mod-arg conversion??? (1 Viewer)

[Michaelmoo]

Find the following in x + iy form:

(3-4i)^5
-----------
(4+3i)^3

Im gettng 24-7i, but the answer says 24 + 7i???

ITs out of the fitzpatrick exercisess...

Thanks

 

[lyounamu]

Find the following in x + iy form:

(3-4i)^5
-----------
(4+3i)^3

Im gettng 24-7i, but the answer says 24 + 7i???

ITs out of the fitzpatrick exercisess...

Thanks

(5(cos(-0.9272...) + isin(-0.9272...))^5/(5(cos0.6435...+isin0.6435...))^3
= (5cis(-0.9272))^5/(5cis(0.6435...)^3
= 25cis(-6.5669...) = 25(cos(-6.5669...) + isin(-6.5669...)) = 24 - 7i

 

[Michaelmoo]

(5(cos(-0.9272...) + isin(-0.9272...))^5/(5(cos0.6435...+isin0.6435...))^3
= (5cis(-0.9272))^5/(5cis(0.6435...)^3
= 25cis(-6.5669...) = 25(cos(-6.5669...) + isin(-6.5669...)) = 24 - 7i

Thanks. Yer this isnt the first mistake in the Fitzpatrick Solutions. To me there seems to be quite a few =/

 

[lyounamu]

Thanks. Yer this isnt the first mistake in the Fitzpatrick Solutions. To me there seems to be quite a few =/

Was the answer wrong?

 

[vds700]

Theres a few mistakes in fitzpatrick answers

 

[Michaelmoo]

Was the answer wrong?

You wern't wrong. The solutions are.