Need help with trig graphing thanks? (1 Viewer)

[CJ251]

Hi everyone. For trig i got this question:
y=cosx-sinx graph this equation.
I know of one way to graph it thanks to pluvia. But how do we graph it using the auxiliary method in other words how do we graph y=sqrt{2}cos(x-pi/4)
Thanks for ur help.

 

[vafa]

you should have y=root2(cosx+pi/4) first you sketch y=root2cosx then you shift it pi/4 units to left

 

[vafa]

There is another so many alternative ways to sketch that function without usin auxillary method. You also could sketch y=sinx+cosx then you would easily sketch the graph of derivative of this which is what you want dy/dx=cosx-sinx

 

[vafa]

this is what I meant by the previous post:

View attachment 13867

 

[CJ251]

this is what I meant by the previous post:

View attachment 13867

Thanks heaps vafa. But when i click to the attatchment it says it's invalid. But it doesnt matter i undertsand it. Thanks again. Good luck. )

 

[vafa]

What about this:
View attachment 13871