C chris_power_96 Member Joined Aug 23, 2011 Messages 111 Gender Undisclosed HSC N/A Aug 13, 2012 #1 x=2(p+q) y=p^(3)+q^(3)
Carrotsticks Retired Joined Jun 29, 2009 Messages 9,494 Gender Undisclosed HSC N/A Aug 13, 2012 #2 y=(p+q)(p^2 - pq + q^2) Note that p^2 + q^2 = (p+q)^2 - 2pq. Now, to finish your question, we need some sort of condition (usually something like pq=-1).
y=(p+q)(p^2 - pq + q^2) Note that p^2 + q^2 = (p+q)^2 - 2pq. Now, to finish your question, we need some sort of condition (usually something like pq=-1).
C chris_power_96 Member Joined Aug 23, 2011 Messages 111 Gender Undisclosed HSC N/A Aug 13, 2012 #3 yeh sorry it was pq=-1
Carrotsticks Retired Joined Jun 29, 2009 Messages 9,494 Gender Undisclosed HSC N/A Aug 13, 2012 #4 Then I guess you're done =)