parametric representation help!! (1 Viewer)
- Thread starter viraj30
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bleakarcher
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y=2x^2
y=m(x+1)
When line and curve intersect,
m(x+1)=2x^2
2x^2-mx-m=0
Discriminant=m^2-4(2)(-m)=m^2+8m
In order for there to be two points of intersection the discriminant must be greater than 0. Hence:
m^2+8m>0
Therefore, m<-8 or m>0
y=m(x+1)
When line and curve intersect,
m(x+1)=2x^2
2x^2-mx-m=0
Discriminant=m^2-4(2)(-m)=m^2+8m
In order for there to be two points of intersection the discriminant must be greater than 0. Hence:
m^2+8m>0
Therefore, m<-8 or m>0