Please Help Me Solve!!!2 (1 Viewer)

[bmcdancer]

Simpify the expression so that no negative exponents appear in the final result. Assume that all variables represent non zero real numbers.




2^3 n^7(n-6)^-1
_____________

2^6 n^-3

 

[lyounamu]

Simpify the expression so that no negative exponents appear in the final result. Assume that all variables represent non zero real numbers.




2^3 n^7(n-6)^-1
_____________

2^6 n^-3

Answer:

n^10
_____________
8(n-6)

 

[bored of sc]

Simpify the expression so that no negative exponents appear in the final result. Assume that all variables represent non zero real numbers.




2^3 n^7(n-6)^-1
_____________

2^6 n^-3

Since it's multiplication and division you can treat each bit like seperate fractions mulitplied together (this will become clearer below).

i.e. 2³/2⁶ * n⁷(n-6)^-1/n^-3

Hopefully it is clearer how you rearrange now.

1/2³ (index law of a^m/aⁿ = a^m-n)* n⁷*n³/(n-6) (move negative power in denominator to numerator to make it positive, vice-versa for power in the numerator).

Now use a^m*aⁿ = a^m+n for n powers on numerator and multiply through each fraction, evaluating where necessary i.e. 2³.

= n¹⁰/8(n-6)

 

[gurmies]

yep, Bored of SC is correct