PLs Complex Numbers Polynomials Questions ASAP Help PLS (1 Viewer)

[Modern4DaBois]

Can someone pls help with Question 17, and Question 16 (part d)?
Thank you so much!

 

[CM_Tutor]

For question 17, a polynomial can inly have a multiple root if there are any -values for which , using the multiple root theorem. If you attempt to solve the equation , you should find it has only one solution, . However, and so the only potential multiple root isn't a root at all, and so there are no multiple roots.

In fact, if is extended to an infinite polynomial, it is the polynomial version of , as indicated by the fact that you then have and thus there are no zeroes of at all.

 

[Modern4DaBois]

For question 17, a polynomial can inly have a multiple root if there are any -values for which , using the multiple root theorem. If you attempt to solve the equation , you should find it has only one solution, . However, and so the only potential multiple root isn't a root at all, and so there are no multiple roots.

In fact, if is extended to an infinite polynomial, it is the polynomial version of , as indicated by the fact that you then have and thus there are no zeroes of at all.

Ah kk That makes sense now. Thanks!
Your explanations are really good btw.

 

[CM_Tutor]

Ah kk That makes sense now. Thanks!
Your explanations are really good btw.

Thank you, I hope that they make sense and help lots of BoS contributors.

 

[5uckerberg]

Q16d
This is going to get an interesting one. First step find the factors of 2702, this is because we are using the product of roots to our advantage. The second step find a ceratin set of factors and then you add and minus them these will form the x squared term. Third step fidn a term that is the square of the x squared terms that you introduced.
Lastly factorise and finish off the question.

 

[Modern4DaBois]

Thx bro that helps a lot!