polynomials...:'( (1 Viewer)

[johnncenaa]

Would someone mind being a legend and explaining the process for answering these types of questions? (kinda in detail as I've tried lots of these and can't seem to get a hang of it)

"when P(x) is divided by x^2 - 1, the remainder is 3x-1. What is the remainder when P(x) is divided by x-1?"

Thanks in advance boses!!

 

[leehuan]

Polynomnomnomnomnomnomnomials (insert pacman)
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So using the division transformation:
P(x) = A(x)Q(x) + R(x)
A(x) = Divisor
Q(x) = Quotient
R(x) = Remainder

We have

P(x) = (x^2-1)Q(x) + (3x-1)
For some arbitrary quotient Q(x)

According to the remainder theorem, the remainder when divided by x-1 is just P(1) because it's a linear divisor.

So P(1) = (1^2-1)Q(x) + (3*1 - 1)
= 0 + 3 - 1
= 2

So the remainder is 2

 

[johnncenaa]

Much love leehuan <3

wew I actually get it now!