Probability Distributions Question (1 Viewer)

[hmim]

Hi,

Could someone, please kindly explain how they got the values for the probabilities in the table above.

 

[carrotsss]

The chance of x=0 is:

• When picking the first wallaby, there are 20 wallabies available and 11 of them aren’t from acacia flat (based on original numbers from question)
• When picking the second wallaby, there are 19 wallabies available and 10 of them aren’t from acacia flat (because we just took one)
• When picking the third wallaby, there are 18 wallabies available and 9 of them aren’t from acacia flat (because we’ve taken two)

So (11/20)*(10/19)*(9/18)=11/76

Repeat a similar process to find the rest of them

 

[hmim]

The chance of x=0 is:

• When picking the first wallaby, there are 20 wallabies available and 11 of them aren’t from acacia flat (based on original numbers from question)
• When picking the second wallaby, there are 19 wallabies available and 10 of them aren’t from acacia flat (because we just took one)
• When picking the third wallaby, there are 18 wallabies available and 9 of them aren’t from acacia flat (because we’ve taken two)

So (11/20)*(10/19)*(9/18)=11/76

Repeat a similar process to find the rest of them

thank you so much, that makes sense!