Projectile Help (1 Viewer)

[azureus88]

A particle is projected with speed "V" m/sec from a height of "a" metres above a horizontal plane at an angle of elevation of @ degrees to the horizontal. If the range is "R", prove that:

(sec^2@)(R^2) - 2(V^2/g)(tan@)R - (2aV^2)/g = 0

 

[Pwnage101]

basically derive the equations of morion in horizontal/vertical components

then use these to form teh cartesian equation

then, sub in (R, 0) into the cartesian, as this satisfies teh equation

then rearrange

and you get that

i suck at writing the working out fully on PC, anyone else bothered?

 

[azureus88]

ok dont worry bout it, i got it, thanks

 

[Pwnage101]

no probs, happy 2 help