J Jaguar33 Member Joined Mar 29, 2014 Messages 36 Gender Female HSC 2015 Sep 14, 2014 #1 Find the values of n in the equation 2x^2-5(n-1)x +12 = 0 If the two roots are consecutive. thanks whoever helps! much appreciated!
Find the values of n in the equation 2x^2-5(n-1)x +12 = 0 If the two roots are consecutive. thanks whoever helps! much appreciated!
Trebla Administrator Administrator Joined Feb 16, 2005 Messages 8,401 Gender Male HSC 2006 Sep 14, 2014 #2 Jaguar33 said: Find the values of n in the equation 2x^2-5(n-1)x +12 = 0 If the two roots are consecutive. thanks whoever helps! much appreciated! Click to expand... Let a and (a+1) be the roots of the equation. Use the product of roots to solve for a and then use the sum of the roots to solve for n.
Jaguar33 said: Find the values of n in the equation 2x^2-5(n-1)x +12 = 0 If the two roots are consecutive. thanks whoever helps! much appreciated! Click to expand... Let a and (a+1) be the roots of the equation. Use the product of roots to solve for a and then use the sum of the roots to solve for n.
P photastic Well-Known Member Joined Feb 11, 2013 Messages 1,848 Gender Male HSC 2014 Sep 14, 2014 #3 Jaguar33 said: Find the values of n in the equation 2x^2-5(n-1)x +12 = 0 If the two roots are consecutive. thanks whoever helps! much appreciated! Click to expand...
Jaguar33 said: Find the values of n in the equation 2x^2-5(n-1)x +12 = 0 If the two roots are consecutive. thanks whoever helps! much appreciated! Click to expand...