V Volarath New Member Joined Feb 28, 2006 Messages 10 Gender Male HSC 2006 May 6, 2006 #1 (x + y + z)<sup>2</sup> = ??? I seem to recall some pyramidal pattern for doing these things... Any help appreciated.
(x + y + z)<sup>2</sup> = ??? I seem to recall some pyramidal pattern for doing these things... Any help appreciated.
volition arr. Joined Oct 28, 2004 Messages 1,279 Location Sydney Gender Male HSC 2005 May 6, 2006 #2 I think its: 2 (xy + xz+ yz) + x^2 + y^2 + z^2 kinda like two times the products of the thing plus the squares of each one individually
I think its: 2 (xy + xz+ yz) + x^2 + y^2 + z^2 kinda like two times the products of the thing plus the squares of each one individually
S SoulSearcher Active Member Joined Oct 13, 2005 Messages 6,757 Location Entangled in the fabric of space-time ... Gender Male HSC 2007 May 6, 2006 #3 volition said: I think its: 2 (xy + xz+ yz) + x^2 + y^2 + z^2 kinda like two times the products of the thing plus the squares of each one individually Click to expand... That's correct.
volition said: I think its: 2 (xy + xz+ yz) + x^2 + y^2 + z^2 kinda like two times the products of the thing plus the squares of each one individually Click to expand... That's correct.
Slidey But pieces of what? Joined Jun 12, 2004 Messages 6,600 Gender Male HSC 2005 May 7, 2006 #4 What about (x+y+z)^3? What about 4, 5...? There is a pattern much like the binomial theorem. Can you find it?
What about (x+y+z)^3? What about 4, 5...? There is a pattern much like the binomial theorem. Can you find it?
Wackedupwacko Member Joined Nov 29, 2005 Messages 141 Location Sydney Gender Male HSC 2006 May 10, 2006 #5 o its not a hard thing (x+y+z)³ = 1(x³+y³+z³) + 3(x²y+x²z+y²x+y²z+z²x+z²y)+3(xyz) similar to binomial theorem eg (x+y+z)^4 1(x^4+y^4+z^4) + 4(1 cube term 1 other) +6(2square terms) +4(1square an the other 2) etc etc
o its not a hard thing (x+y+z)³ = 1(x³+y³+z³) + 3(x²y+x²z+y²x+y²z+z²x+z²y)+3(xyz) similar to binomial theorem eg (x+y+z)^4 1(x^4+y^4+z^4) + 4(1 cube term 1 other) +6(2square terms) +4(1square an the other 2) etc etc