okay so I am aware that when f"(x)=0, it can be an inflexion point, max, min, anything really..... am I right?
WHY THEN, IS F'(2)=F"(2)=0 A HORIZONTAL POINT OF INFLEXION? can't it also be a turning point?
I AM SO CONFUSED.
thank you
!!
F'(2)=F"(2)=0
does not necessary imply A HORIZONTAL POINT OF INFLEXION
You need to verify there's a change of concavity
i.e. F''(x) has opposite signs to either side of x=2
e.g. for f(x)= x^3
f''(0)=f'(0)=0
ALSO, f''(x)>0 for x>0 , f''(x)<0 for x<0 ====> f'' has opposite signs, concavity changes
Hence (0,0) is a horizontal point of inflexion
Whereas in your case , you can just for example take F(x)=(x-2)^4
then the condition F'(2)=F"(2)=0 is satisfied
but F''(x)=12*(x-2)^2 > 0 to either side of x=2 ====> F'' has the same sign, concavity DOES NOT change
So the point (2,0) is NOT a horizontal point of inflexion
And it is actually a minimum by finding the signs of F'(x)
Anyways, what I want to say is that :
You ALWAYS need to check the change in sign of f'' (hence change of concavity) for a point of inflexion