You can also treat it as a sequence and series problem, with the profit in the first year being
![](https://latex.codecogs.com/png.latex?\bg_white \$P)
and the common ratio being
![](https://latex.codecogs.com/png.latex?\bg_white 1 + \frac{14}{100} = 1.14)
so that you have a sequence of profits in successive years of
![](https://latex.codecogs.com/png.latex?\bg_white P,\ 1.14P,\ 1.14^2P,\ 1.14^3P,\ ...)
And you seek year
![](https://latex.codecogs.com/png.latex?\bg_white n)
, being the smallest value of
![](https://latex.codecogs.com/png.latex?\bg_white n)
satisfying the equation
![](https://latex.codecogs.com/png.latex?\bg_white \text{Profit}\ = 1.14^{n-1}P >20P)
... So, in year 24 or after 23 full years.