blackops23
Member
- Joined
- Dec 15, 2010
- Messages
- 428
- Gender
- Male
- HSC
- 2011
Hi guy's just something I'm curious about involving velocity, specifically in the situation where there is simple harmonic motion.
So we know the expression that v^2 = (n^2)(a^2 - x^2) --> where a refers to amplitude (maximum displacement).
And thus v = +/- (n)[(a^2 - x^2)^0.5] ------- (1)
--------------
However.... we know that x = a(cos(nt + alpha))
Therefore: dx/dt = -(n)(a)*[sin(nt + alpha)]
v= dx/dt
therefore v = -n(a)[sin(nt+alpha)] ------------------------ (2)
So we clearly have two expressions for v... are they both equal?
i.e. is -nasin(nt+alpha) = +/- n(a^2 - x^2)^0.5
and thus, is asin(nt+alpha) = +/-(a^2 - x^2)^0.5?
Or did I do something horribly wrong? Because I just can't see how they are equal...
Thanks, help is immensely appreciated.
So we know the expression that v^2 = (n^2)(a^2 - x^2) --> where a refers to amplitude (maximum displacement).
And thus v = +/- (n)[(a^2 - x^2)^0.5] ------- (1)
--------------
However.... we know that x = a(cos(nt + alpha))
Therefore: dx/dt = -(n)(a)*[sin(nt + alpha)]
v= dx/dt
therefore v = -n(a)[sin(nt+alpha)] ------------------------ (2)
So we clearly have two expressions for v... are they both equal?
i.e. is -nasin(nt+alpha) = +/- n(a^2 - x^2)^0.5
and thus, is asin(nt+alpha) = +/-(a^2 - x^2)^0.5?
Or did I do something horribly wrong? Because I just can't see how they are equal...
Thanks, help is immensely appreciated.
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