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sin^2x & cos^2x (1 Viewer)

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Primitive function of
a) 3sin^2 2x/5
b) sin^3 xdx <---- use substitution right???
 

GUSSSSSSSSSSSSS

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(a) same as last trigonometry thread u posted, convert (sinx)^2 to (1/2)(cos2x -1)

(b) yea!!
 

Timothy.Siu

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a) 3sin^2 2x/5=3/2 (cos 4x/5-1)
primtive, 3/2(5/4 sin 4x/5-x)+C

b) sin^3 xdx
S sin^3 xdx=Ssinx(1-cos^2x)dx=S(sinx-cos^2 xsinx)dx=-cosx+cos^3 x/3+C
 
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is it suppose to be 3/2(4/5cos4x/5-x)+c???
or like above, if so why do you flip the 4/5???

I understand now, got it :)p
 
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