Y YashC3 Member Joined Jul 18, 2009 Messages 49 Gender Male HSC 2010 Mar 14, 2010 #1 aye guys, I came across a couple of graphs when doin inverse trig that I could't sketch. Any help would be appreciated. 1) y = sin (cos inverse x) 2) y= sin inverse (cos x) 3) x= tan y -3pi/ 2 < x < 3pi/2 Thanks
aye guys, I came across a couple of graphs when doin inverse trig that I could't sketch. Any help would be appreciated. 1) y = sin (cos inverse x) 2) y= sin inverse (cos x) 3) x= tan y -3pi/ 2 < x < 3pi/2 Thanks
xV1P3R Member Joined Jan 1, 2007 Messages 199 Gender Male HSC 2010 Mar 14, 2010 #2 1) Let theta = arccos(x) Draw the triangle represented by this ie. angle theta, side adjacent to theta = x, hypotenuse = 1, solve for other side which is 2) Same strategy 3) should be able to graph y=arctan(x) yes?
1) Let theta = arccos(x) Draw the triangle represented by this ie. angle theta, side adjacent to theta = x, hypotenuse = 1, solve for other side which is 2) Same strategy 3) should be able to graph y=arctan(x) yes?
