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Tan^2X (1 Viewer)

Thread starter starlitwonder
Start date May 8, 2006

S

starlitwonder

Member

#1

Help! How do I differentiate y=Tan^2X

S

SoulSearcher

Active Member

#2

Chain rule, I would think
y = tan²x = (tan x)²
Therefore
y' = 2 tan x * d/dx(tan x)
= 2 tan x * sec²x

S

sasquatch

Member

#3

Very simply:

Let y = tan²x
= [tanx]²

dy/dx = 2[tanx]sec²x

EDIT: well i see someone beat me... not my fault im a couple seconds slow...

Last edited: May 8, 2006

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