Find the point of intersection of the normals to the parabola x^2= - 12y at the points (4,-1/3) and (-2, -1/3).
Do I have to find TWO normals (one for the point 4, -1/3) and another for the point (-2, -1/3) and then solve them simulataneously?
Any help would be much appreciated.
Do I have to find TWO normals (one for the point 4, -1/3) and another for the point (-2, -1/3) and then solve them simulataneously?
Any help would be much appreciated.