凍 凍鴛鴦 Member Joined Nov 10, 2004 Messages 53 Gender Undisclosed HSC 2006 Oct 9, 2005 #1 Hi, How do you proof that LHS = RHS given LHS = Sqrt(3)*Cos[3t]-Sin[3t] RHS = 2Cos[3t + pi/6] ?? Thanks!
Hi, How do you proof that LHS = RHS given LHS = Sqrt(3)*Cos[3t]-Sin[3t] RHS = 2Cos[3t + pi/6] ?? Thanks!
Jago el oh el donkaments Joined Feb 21, 2004 Messages 3,691 Gender Male HSC 2005 Oct 9, 2005 #2 auxiliary angle method i presume. aka let root3 Cos3t - Sin3t = Rcos(x + @)
haboozin Do you uhh.. Yahoo? Joined Aug 3, 2004 Messages 708 Gender Male HSC 2005 Oct 9, 2005 #3 凍鴛鴦 said: Hi, How do you proof that LHS = RHS given LHS = Sqrt(3)*Cos[3t]-Sin[3t] RHS = 2Cos[3t + pi/6] ?? Thanks! Click to expand... expand RHS 2(cos3tcos(pi/6) -sin3tsinpi/6) 2Sqrt(3)/2cos3t - 2/2sin3t sqrt(3)cos3t - sin3t = LHS
凍鴛鴦 said: Hi, How do you proof that LHS = RHS given LHS = Sqrt(3)*Cos[3t]-Sin[3t] RHS = 2Cos[3t + pi/6] ?? Thanks! Click to expand... expand RHS 2(cos3tcos(pi/6) -sin3tsinpi/6) 2Sqrt(3)/2cos3t - 2/2sin3t sqrt(3)cos3t - sin3t = LHS
凍 凍鴛鴦 Member Joined Nov 10, 2004 Messages 53 Gender Undisclosed HSC 2006 Oct 9, 2005 #4 D'oh, can't believe I didn't see that. Thanks guys!
