Trig Integration Prob (1 Viewer)

Sarah168

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Does anybody know how to integrate:

sec x tan x dx

the answer is sec x + c

Is there a way to do it without going backwards and differentiating sec x ?
 

redruM

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i knew how this worked....i've forgotten all maths!
edit: doesnt it work with just using the table of integrals.
 
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it's a standard integral.

or if you insist, secxtanx = sinx/cos^2x
Let u = cosx, du=-sinxdx
secxtanx = -1/u^2
integral: 1/u +c
= 1/cosx +c
= secx +c
 

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