Trig (1 Viewer)

yeyjasminetime · Nov 9, 2013

Hi! How would you find the value of this?

Trebla · Nov 9, 2013

Recall that

$\displaystyle\lim_{x\rightarrow 0}\dfrac{\sin x}{x}=1$

Replace x with ax then

$\displaystyle\lim_{ax\rightarrow 0}\dfrac{\sin (ax)}{ax}=1$

But ax approaching zero is equivalent to x approach zero so

$\displaystyle\lim_{x\rightarrow 0}\dfrac{\sin (ax)}{ax}=1$

Now manipulate your expression to look like this (i.e. multiplying and dividing constants to numerator and denominator) and apply the result.

phoenix159 · Nov 9, 2013

The answer is 6/5

Trebla · Nov 9, 2013

The answer is 15/2

QZP · Nov 9, 2013

@Trebla, for $\displaystyle\lim_{x\rightarrow 0}\dfrac{\sin x}{x}=1$

When do I learn this? I've done trigonometry but havn't come across it

Trebla · Nov 9, 2013

QZP said:
@Trebla, for $\displaystyle\lim_{x\rightarrow 0}\dfrac{\sin x}{x}=1$

When do I learn this? I've done trigonometry but havn't come across it

This is in the Further Trigonometry topic which is usually covered in Year 12.

phoenix159 · Nov 14, 2013

QZP said:
@Trebla, for $\displaystyle\lim_{x\rightarrow 0}\dfrac{\sin x}{x}=1$

When do I learn this? I've done trigonometry but havn't come across it

You usually do it as part of differential calculus when you differentiate trig functions

hit patel · Nov 14, 2013

Yes it is called trig functions and comes within differential and integral of trig functions topic but before that.

Trig (1 Viewer)

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