This is my attempt:
The maximum y is when x = sqrt(3) so y = 9
Hence volume is I{0->9} Pi*(x<sub>1</sub><sup>2</sup> - x<sub>2</sub><sup>2</sup>)dy
now y = 6x<sup>2</sup> - x<sup>4</sup>
so (x<sup>2</sup>)<sup>2</sup> - 6(x<sup>2</sup>) + y = 0
Solving quadratically we get:
x<sup>2</sup> = [6 +/- sqrt(36-4y) ] / 2
so x<sub>1</sub><sup>2</sup> - x<sub>2</sub><sup>2</sup> = sqrt(36-4y)
so V = I{0->9} Pi * sqrt(36-4y) dy
and then i get V = 36 Pi
Have not done a volume question for a year, pls verify my result. Thanks