w/v calculation (1 Viewer)

[Aqua10]

Could anyone please answer the following question with relevant working?

If sulphuric acid used for hydrolysis is 7.34% w/v, what is its concentration in mol/L?

 

[tennille]

7.34% (w/v) is 7.34 g/100 mL, which is equivalent to 73.4 g/L. The molecular weight of sulfuric acid is 98.08 g/mol. If you're not sure about the calculations, you could just look at the units. You have g/L and g/mol, and you want to get mol/L In this case, we divide. So (73.4 g/L)/(98.08 g/mol). The g's cancel out, and the mol would then be a multiple up the top, so you get 0.75 mol/L.

 

[Aqua10]

Thanks