I intuiit Member Joined Jan 28, 2008 Messages 54 Gender Undisclosed HSC N/A Oct 6, 2008 #1 This is the one on 'winkler method'. 0.6 moles of thiosulfate added - how many moles of oxygen and whenever I backtrack through the three equations, i keep getting 0.3 mol O2!!!! WHY?! Please Help!! :mad1:
This is the one on 'winkler method'. 0.6 moles of thiosulfate added - how many moles of oxygen and whenever I backtrack through the three equations, i keep getting 0.3 mol O2!!!! WHY?! Please Help!! :mad1:
A Azreil Member Joined May 28, 2007 Messages 274 Gender Female HSC 2008 Oct 7, 2008 #2 2S2O3 = 0.6 moles I2 = 0.3 moles Therefore MnO(OH)2 = 0.3 moles Therefore O2 = 0.15 moles You interpreted the final equation wrong. Thiosulfate is on the reactants side, not the products side. At least, that's what I'm guessing.
2S2O3 = 0.6 moles I2 = 0.3 moles Therefore MnO(OH)2 = 0.3 moles Therefore O2 = 0.15 moles You interpreted the final equation wrong. Thiosulfate is on the reactants side, not the products side. At least, that's what I'm guessing.
