In the jacaranda textbook pg 468 how did they get the value of 4.032980?
when i do it using the data sheet from bos, i do
2x (9.109 x 10^-31 + 1.675 x 10^-27 + 1.673 x 10^-2) / (1.661 x 10^-27) = 4.03240 which is different to the book.
and also how do you work out the mass of the original helium atom which is 4.002603 in the exam? what values do they normally to give to you in the exam?
when i do it using the data sheet from bos, i do
2x (9.109 x 10^-31 + 1.675 x 10^-27 + 1.673 x 10^-2) / (1.661 x 10^-27) = 4.03240 which is different to the book.
and also how do you work out the mass of the original helium atom which is 4.002603 in the exam? what values do they normally to give to you in the exam?