Help in sin^2x and cos^2x :S (1 Viewer)

[Ryuu-jin-jakka]

a) sin^3 x
b) sin^2 x^o (degree)

 

[Ryuu-jin-jakka]

anyone :S

 

[Drongoski]

a) sin^3 x
b) sin^2 x^o (degree)

What's your question ? ? ?

 

[Drongoski]

If you are seeking the primitives:

 

[Ryuu-jin-jakka]

my bad, its integrating it

 

[Drongoski]

I don't know why my answer to a) came out tiny?

 

[Ryuu-jin-jakka]

huh, its x^3, y no 1/3cos3^ x

 

[Ryuu-jin-jakka]

aswner for a is -cosx + 1/3cos^3 x

 

[Ryuu-jin-jakka]

i think you got it right , but you seem to skip some step, slow person, can you show the full working out

 

[Drongoski]

 

[Drongoski]

aswner for a is -cosx + 1/3cos^3 x

I'll get back later. Have to watch my mid-day news. Also I can get all the integration problems out quickly; problem is unlike you youngsters my typing is slow!

 

[Drongoski]

i think you got it right , but you seem to skip some step, slow person, can you show the full working out

I have not skipped any steps; it's just that my approach is different. Now how do I get LaTeX here? You see I'm struggling to use things you guys take for granted.

 

[Drongoski]

Hey guys . . after posting all those solutions I'd have thought there'd be some recognition by way of reputatation points. Got zilch !

 

[Prashant Sallan]

Hey guys . . after posting all those solutions I'd have thought there'd be some recognition by way of reputatation points. Got zilch !

hey.. howd u integrate the sin^2x cosx?

 

[tommykins]

it is in the form of f'(x).f(x) meaning sin^2x.cosx integrated is simply (sin^3 x)/3

 

[kwabon]

hey.. howd u integrate the sin^2x cosx?

u substitutions

let u = sinx
and wallah .... bob is ur uncle

 

[Prashant Sallan]

OMG..!! i always forget that rule..

Thank You/

 

[addikaye03]

a) sin^3 x
b) sin^2 x^o (degree)

a) Ill give you a hint. Expand Sin3x ie. Sin(2x+x) then get the equation in terms of sin, and there might just be a -4sin^3x or whatever it is in there, then rearrange.

 

[Timothy.Siu]

If you are seeking the primitives:

u forgot the minus sign, d/dx(cos x)=-sin x

 

[Timothy.Siu]

a) Ill give you a hint. Expand Sin3x ie. Sin(2x+x) then get the equation in terms of sin, and there might just be a -4sin^3x or whatever it is in there, then rearrange.

its not sin 3x its sin^3 x

u substitutions

let u = sinx
and wallah .... bob is ur uncle

substitutions is slow for this, u shudn't need it