MONKEYjulz
Member
Is my solution correct?
Given P(x) = 4x^3 - 27x + k has a double root. Find possible values for k.
P'(x) = 12x^2 - 27
P'(x) = 0
x^2 = 27/12
x= +/- 3/2
P(3/2) = 27/2 - 81/2 + k = 0
P(-3/2) = -27/2 + 81/2 + k = 0
k = 54/2 = 27
k = -54/2 = -27
Help is appreciated.
Given P(x) = 4x^3 - 27x + k has a double root. Find possible values for k.
P'(x) = 12x^2 - 27
P'(x) = 0
x^2 = 27/12
x= +/- 3/2
P(3/2) = 27/2 - 81/2 + k = 0
P(-3/2) = -27/2 + 81/2 + k = 0
k = 54/2 = 27
k = -54/2 = -27
Help is appreciated.