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Inverse Question (1 Viewer)

water89

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Hey guys,

Not really too sure how to do this, please help...

Use the differential of y= cos^-1 (sin x) or otherwise to sketch y= cos^-1 (sinx) for x between negative 2 pi and 2 pi.
 

omniscience

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Hey guys,

Not really too sure how to do this, please help...

Use the differential of y= cos^-1 (sin x) or otherwise to sketch y= cos^-1 (sinx) for x between negative 2 pi and 2 pi.
solve
i) 2 - 5 =
ii) 3 - 2 =
iii) x^19211231204921038123908120512957124812039813102310238120830218301283012830281308123081203801280123 = 3
 

gurmies

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It's only the cosine that is inverse according to his/her question.



I suppose I would sub simple points, noting that the gradient fluctuates between 1 and -1...Also well worth noting is that the derivative is not existent for some values of x. Expect to see jagged points in your graph...
 
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GUSSSSSSSSSSSSS

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Also well worth nothing is that the derivative is not existent for some values of x. Expect to see jagged points in your graph...


o_O ...........sounds like someone's done this question before xD

......but yea he is right, its basically a crooked line between y=pi and y=0
 
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gurmies

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o_O ...........sounds like someone's done this question before xD

......but yea he is right, its basically a crooked line between y=1 and y=-1
=D I'm glad it comes across like that, but this is my first time on a question like this. It's only logical to expect cusps where the derivative doesn't exist xD
 

GUSSSSSSSSSSSSS

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ohhhhhhhhhhhhhhhh well fair enuf then xD

logical thinking ftw !!!!

btw i made a typo its y = pi and y = 0 not y = 1 and y = -1
 

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